A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) Pyridine will deprotonate the amine or alcohol, making it a better nucleophile.
B) Pyridine will neutralize the acid by-product of the reaction.
C) Pyridine will protonate the carbonyl of the acid chloride, making it more reactive.
D) Pyridine will absorb the heat of the reaction.
Correct Answer
verified
Multiple Choice
A) n-Butane nitrile will react with ethylmagnesium bromide to form an alcohol.
B) n-Butanenitrile with be reduced to butyl amine in the presence of LiAlH4 with an aqueous work-up.
C) n-Butanenitrile is hydrolyzed in the presence of acid to form butanoic acid.
D) n-Butanenitrile is reduced with DIBAL-H to form n-butanal.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) Methyl 3-methylbutanamide
B) 5-Methylhexanamide
C) N-Methyl 3-methylhexanamide
D) N-Methyl 3-methylbutanamide
Correct Answer
verified
Multiple Choice
A) Hexanoic acid
B) 1-Hexanamide
C) Hexanal
D) 1-Hexanamine
Correct Answer
verified
Multiple Choice
A) 2.5 ppm
B) 2250 cm-1
C) 3800 cm-1
D) 1740 cm-1
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) a carboxylic acid.
B) a nitrile.
C) an aldehyde.
D) an anhydride.
Correct Answer
verified
Multiple Choice
A) A ketone
B) An aldehyde
C) An ester
D) A nitrile
Correct Answer
verified
Multiple Choice
A) I, because it is less hindered
B) II, because it is less hindered
C) I, because it is more strained
D) II, because it is more strained
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) RCOCl + R'NH2 + pyridine
B) RCOOH + R'OH + H+
C) RCOOH + R'OH + OH-
D) D. RCONH2 + R'OH
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
Multiple Choice
A) 4-Fluoro-3-methylbenzoate
B) 4-Fluoro-3-methylbenzoic acid
C) 3-Methyl-4-fluorobenzoic acid
D) 4-Fluoro-5-methylbenzoic acid
Correct Answer
verified
Multiple Choice
A) A flat line (carboxylic acids are not IR active)
B) A sharp line at 2250 cm-1
C) A broad peak from 3800-2800 cm-1
D) A broad peak from 800-600 cm-1
Correct Answer
verified
Multiple Choice
A) Nitrogen is a better leaving group.
B) Chloride is a better leaving group.
C) Nitrogen donates more electron density into the carbonyl.
D) The amide anion is less basic.
Correct Answer
verified
Multiple Choice
A) I
B) II
C) III
D) IV
Correct Answer
verified
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